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Exponential Distribution Calculator

Work with the exponential distribution using rate lambda. Find probabilities, survival, and key stats for waiting time and reliability problems.

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  1 divided by the average number of events per time period.



Result will appear here...


Last updated: April 9, 2026

Created by: Eon Tools Dev Team

Reviewed by: Ankit Khatiwada



What the exponential distribution calculator does

The exponential distribution describes the waiting time until the next random event, when events happen at a steady average rate. This calculator takes the rate and a length of time and returns the chance the wait is longer or shorter than that, along with the mean, median, variance, and standard deviation.

It is the standard model for gaps between events and for how long things last before they fail. Below is how it works and where it fits among the distributions.

How to use it

  1. Enter the rate parameter, the average number of events per unit of time.
  2. Enter a time, the waiting period you are asking about.
  3. Press Calculate for the probabilities and the summary measures, or Reset to clear it.

The distribution of waiting times

Where the distributions covered so far count things, the exponential measures time, a continuous quantity. It answers questions like how long until the next customer arrives, the next call comes in, or a component fails. The rate parameter sets how often events happen, and from it the whole distribution of waiting times follows.

Its shape is a curve that is highest near zero and tails off. That means short waits are the most common and long waits get steadily rarer, which matches everyday experience: most gaps between random events are short, with the occasional long lull. The mean wait is simply one divided by the rate, so a faster rate means shorter typical waits.

How the probabilities are worked out

The chance that the wait is longer than a time x, the survival probability, falls off exponentially with that time:

P(wait > x) = e(minus rate × x)

Here e is the constant about 2.718. The chance the wait is x or less is just one minus that. As the time grows, the survival probability shrinks toward zero, quickly when the rate is high and slowly when it is low. The calculator also reports the mean as one over the rate, the median as a little less than the mean, and the variance, all following directly from the rate.

Its link to the Poisson distribution

The exponential is the natural partner of the Poisson distribution, and they describe the same process from two angles. If events arrive at a constant average rate, the Poisson counts how many land in a fixed interval, while the exponential measures the time between one event and the next. The same rate parameter drives both.

So they are two views of a single random process: one about counts, the other about gaps. If calls arrive as a Poisson process averaging three an hour, the number of calls in an hour is Poisson, and the minutes between calls are exponential. Seeing them as a pair makes both easier to reason about.

The memoryless property

Like its discrete relative the geometric distribution, the exponential is memoryless. However long you have already waited, the chance of waiting a further stretch is exactly the same as if you had just started. The past does not shorten the remaining wait.

This can feel strange but it is the mathematical meaning of "random and rateless in memory". If buses truly arrive as random events at a constant rate, then having waited ten minutes tells you nothing about how much longer you will wait. It is worth knowing that this is an assumption of the model. Real waits often are not memoryless, which is a sign that a constant random rate may not be the right description.

A worked example

Suppose events happen at a rate of 0.5 per hour, meaning one every two hours on average, and you ask about a wait longer than 3 hours.

The survival probability is e raised to minus 0.5 times 3, that is e-1.5, about 22.3 percent. So there is roughly a 22 percent chance of waiting more than 3 hours, and about 77.7 percent of waiting less. The mean wait is one divided by 0.5 = 2 hours, and the median is a bit under 1.4 hours, shorter than the mean because the long waits pull the average up.

Entering your values

Enter the rate as a positive number, matching the time unit you care about, so a rate per hour answers questions in hours. Enter the time as a positive number too. The calculator returns the chance of a longer and a shorter wait, plus the mean, median, variance, and standard deviation, all set by the rate.

Questions people ask

What is the exponential distribution?

The distribution of the waiting time until the next event when events occur at a constant average rate. Short waits are most likely, long waits progressively rarer.

How does it relate to the Poisson distribution?

They describe the same process. The Poisson counts events in an interval; the exponential measures the time between events. The same rate drives both.

What is the mean wait?

One divided by the rate. At a rate of 0.5 events per hour, the mean wait is 2 hours.

What does memoryless mean here?

That time already spent waiting does not change the remaining wait. Having waited a while leaves the chance of waiting longer unchanged, which is an assumption of the model.

References

A quick note on where the methods here come from. The exponential distribution is set out in the NIST/SEMATECH e-Handbook of Statistical Methods, the US government's public statistics reference. OpenStax Introductory Statistics is a free, widely used textbook covering the exponential distribution.

  1. NIST/SEMATECH e-Handbook of Statistical Methods (the exponential distribution). https://www.itl.nist.gov/div898/handbook/
  2. OpenStax, Introductory Statistics (the exponential distribution). https://openstax.org/details/books/introductory-statistics-2e


Ankit Khatiwada

Ankit Khatiwada is a researcher and graduate student in Computer Science at Saarland University, with strengths in statistics, data analysis, data engineering, and full stack development. His work sits at the intersection of quantitative reasoning and applied technology, making him a strong fit for tools that depend on clear numerical logic. At Eon Tools, he reviews number and statistical tools.